日本語のみで絞り込む
2009/5/13 -I think you are using 'global' incorrectly. See Python reference. You should declare variable without global and then inside the function ...
2023/9/27 -This error is a type of UnboundLocalError , which is raised when a local variable is referenced before it has been assigned in the local scope.
2023/1/24 -The solution is to tell Python that the local one is the same as the global one by adding the line: global BackLight_Val. in the function ...
2026/10/1 -UnboundLocalError occurs when Python tries to access a local variable before that variable has been assigned a value.
2022/8/31 -To assign to global variables from within functions, you need to mark them explicitly by using the global keyword. So in your case, put the line ...
2026/7/3 -Because index is defined globally as well as inside the foo() function, Python throws an exception if you try to use the variable inside foo ...
Looks like it is becasue you cannot modify a global variable (on_off) inside a function without declaring it as global. That may be the solution but the cause ...
2020/8/10 -You can solve this error by ensuring that a local variable is declared before you assign it a value. Now you're ready to solve UnboundLocalError ...
2022/8/23 -An UnboundLocalError is raised when a local variable is referenced before it has been assigned. In most cases this will occur when trying to ...
2020/1/13 -In Python, variables that are only referenced inside a function are implicitly global. If a variable is assigned a value anywhere within the ...