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2010/4/9 -The Explanation. Whenever a value is assigned to a variable inside a function, python considers that variable a local variable of that function.
2025/7/23 -This error occurs when a local variable is referenced before it has been assigned a value within a function or method. This error typically ...
2023/6/21 -When you assign to a variable in a function, Python assumes that the variable is local to that function unless it's declared in the function ...
2022/1/29 -On line 11, I get UnboundLocalError: local variable 'isTreeBalanced' referenced before assignment. I am trying to access isTreeBalanced ...
2026/10/1 -UnboundLocalError occurs when Python tries to access a local variable before that variable has been assigned a value.
Global variables can be accessed inside and outside a function, while local variables only exist within the function. Nested functions allow defining functions ...
2025/4/10 -The problem is I am now getting an error 'UnboundLocalError: local variable 'var' referenced before assignment'. Below is a side by side ...
In my_adder, the variable out is a local variable. That is, it is only defined in the function of my_adder. Therefore, it cannot affect variables outside of the ...
2017/6/11 -... local variable 'i' referenced before assignment. We can workaround by using a global variable like so: i = 0 def hello(who): greeting ...
In Python, a nested scope refers to the ability of an inner function to access variables from its containing or enclosing function.