nPr = n!/(n-r)! Formula for combination: nCr = n!/r!.(n-r)! ... *In permutations, the order matters*, so rearranging the order of selected objects results in ...
So the formula for calculating the number of combinations is the number of permutations/k!. the number of permutations is equal to n!/(n-k)! so the number of ...
The flips permutations that would result in 2 heads are AB, AC, BC, BA, CB, CA. This is a total of 6 (3x2) permutations. We get the number of combinations by ...